web analytics

Ex 7.2, 2 - In ABC, AD is the perpendicular bisector of BC - Opposite Angles of equal sides

  1. Chapter 7 Class 9 Triangles
  2. Serial order wise
Ask Download

Transcript

Ex7.2, 2 In ΔABC, AD is the perpendicular bisector of BC (see the given figure). Show that ΔABC is an isosceles triangle in which AB = AC. Given: Line AD is perpendicular to BC So, ∠ADC =∠ADB = 90° & Line AD bisects line BC (as it is perpendicular bisector) BD = CD To prove: Δ ABC is isosceles, i.e. AB = AC Proof: In ΔABD and ΔACD, AD = AD ∠ADB = ∠ADC BD = CD ∴ ΔADC ≅ ΔADB ∴ AB = AC Therefore, ABC is an isosceles triangle in which AB = AC. Hence proved

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.
Jail