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Ex 7.2, 4 - ABC is a triangle in which altitudes BE & CF - Opposite Angles of equal sides

Ex 7.2, 4 - Chapter 7 Class 9 Triangles - Part 2
Ex 7.2, 4 - Chapter 7 Class 9 Triangles - Part 3

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Ex7.2, 4 ABC is a triangle in which altitudes BE and CF to sides AC and AB are equal (see the given figure). Show that (i) ABE ACF (ii) AB = AC, i.e., ABC is an isosceles triangle. Comparison with Ex 7.2 , 3 In Ex 7.2 , 3 AB = AC given , we have to prove BE = CF In Ex 7.2 , 4 Here, BE = CF given , we have to prove AB = AC Ex7.2, 4 ABC is a triangle in which altitudes BE and CF to sides AC and AB are equal (see the given figure). Show that (i) ABE ACF (ii) AB = AC, i.e., ABC is an isosceles triangle. Given: BE = CF BE and CF are altitudes. So, AEB = 90 and AFC = 90 To prove: ABE ACF & AB = AC Proof: In ABE and ACF, AEB = AFC A = A BE = CF ABE ACF AB = AC Hence proved

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