CBSE Class 10 Sample Paper for 2020 Boards - Maths Standard

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Question 18 (OR 2nd question) - CBSE Class 10 Sample Paper for 2020 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at April 16, 2024 by

If the radii of two concentric circles are 4 cm and 5 cm, then find the length of each chord of one circle which is tangent to the other circle.

If the radii of two concentric circles are 4 cm and 5 cm, then find

Question 18 (OR 2nd question) - CBSE Class 10 Sample Paper for 2020 Boards - Maths Standard - Part 2
Question 18 (OR 2nd question) - CBSE Class 10 Sample Paper for 2020 Boards - Maths Standard - Part 3
Question 18 (OR 2nd question) - CBSE Class 10 Sample Paper for 2020 Boards - Maths Standard - Part 4

 

 

Note : This is similar to Ex 10.2, 7 of NCERT – Chapter 10 Class 10

Check the answer here https://www.teachoo.com/1833/539/Ex-10.2--7---Two-concentric-circles-are-of-radii-5-cm-and-3-cm/category/Ex-10.2/

Transcript

Question 18 (OR 2nd question) If the radii of two concentric circles are 4 cm and 5 cm, then find the length of each chord of one circle which is tangent to the other circle. Given two concentric circles of radius 4 cm and 5 cm Let AB be chord of larger circle which is tangent to smaller circle at point P We need to find length of chord AB Joining OA, OB and OP OA = OB = Radius of larger circle = 5 cm OP = Radius of smaller circle = 4 cm Now, Since AB is tangent to smaller circle ∴ OP ⊥ AB ∴ ∠ OPA = ∠ OPB = 90° Now, we use Pythagoras theorem in both Δ OPB and Δ OPA Using Pythagoras theorem (Hypotenuse)2 = (Height)2 + (Base)2 In right triangle OAP OA2 = OP2 + AP2 52 = 42 + AP2 25 = 16 + AP2 25 – 16 = AP2 AP2 = 9 AP2 = 32 AP = 3 cm In right triangle OPB OB2 = OP2 + BP2 52 = 42 + BP2 25 = 16 + BP2 25 – 16 = BP2 BP2 = 9 BP2 = 32 BP = 3 cm Hence, AB = AP + PB = 3 + 3 = 6 cm

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