If sin πœƒ + cos πœƒ = √2 cos πœƒ, (πœƒ ≠ 90°) then the value of tan πœƒ  is

(a) √2 − 1  (b) √2 + 1  (c) √2  (d) − √2

If sin πœƒ + cos πœƒ = √2 cos πœƒ, then the value of tan πœƒ is - CBSE Class 1

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Question 6 If sin πœƒ + cos πœƒ = √2 cos πœƒ, (πœƒ β‰  90Β°) then the value of tan πœƒ is (a) √2 βˆ’ 1 (b) √2 + 1 (c) √2 (d) βˆ’ √2 Given sin πœƒ + cos πœƒ = √2 cos πœƒ Dividing both sides by cos ΞΈ (sinβ‘πœƒ + cosβ‘πœƒ)/cosβ‘πœƒ = (√2 cosβ‘πœƒ)/cosβ‘πœƒ sinβ‘πœƒ/cosβ‘πœƒ +cosβ‘πœƒ/cosβ‘πœƒ =√2 tan πœƒ+1=√2 tan πœƒ=√2βˆ’1 ∴ Option (a) is correct

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.