Check sibling questions

  If sin πœƒ + cos πœƒ = √2 cos πœƒ, (πœƒ ≠ 90°) then the value of tan πœƒ  is

(a) √2 − 1  (b) √2 + 1  (c) √2  (d) − √2

If sin πœƒ + cos πœƒ = √2 cos πœƒ, then the value of tan πœƒ is - CBSE Class 1

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


Transcript

Question 6 If sin πœƒ + cos πœƒ = √2 cos πœƒ, (πœƒ β‰  90Β°) then the value of tan πœƒ is (a) √2 βˆ’ 1 (b) √2 + 1 (c) √2 (d) βˆ’ √2 Given sin πœƒ + cos πœƒ = √2 cos πœƒ Dividing both sides by cos ΞΈ (sinβ‘πœƒ + cosβ‘πœƒ)/cosβ‘πœƒ = (√2 cosβ‘πœƒ)/cosβ‘πœƒ sinβ‘πœƒ/cosβ‘πœƒ +cosβ‘πœƒ/cosβ‘πœƒ =√2 tan πœƒ+1=√2 tan πœƒ=√2βˆ’1 ∴ Option (a) is correct

Ask a doubt
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.