Β  If sin πœƒ + cos πœƒ = √2 cos πœƒ, (πœƒ β‰  90Β°) then the value of tan πœƒΒ  is

(a) √2 βˆ’ 1Β  (b) √2 + 1Β  (c) √2Β  (d) βˆ’ √2

If sin πœƒ + cos πœƒ = √2 cos πœƒ, then the value of tan πœƒ is - CBSE Class 1

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Question 6 If sin πœƒ + cos πœƒ = √2 cos πœƒ, (πœƒ β‰  90Β°) then the value of tan πœƒ is (a) √2 βˆ’ 1 (b) √2 + 1 (c) √2 (d) βˆ’ √2 Given sin πœƒ + cos πœƒ = √2 cos πœƒ Dividing both sides by cos ΞΈ (sinβ‘πœƒ + cosβ‘πœƒ)/cosβ‘πœƒ = (√2 cosβ‘πœƒ)/cosβ‘πœƒ sinβ‘πœƒ/cosβ‘πœƒ +cosβ‘πœƒ/cosβ‘πœƒ =√2 tan πœƒ+1=√2 tan πœƒ=√2βˆ’1 ∴ Option (a) is correct

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