## Find the value(s) of k for which the quadratic equation

##
x
^{
2
}
+ 2√2 kx + 18 = 0 has equal roots

Last updated at Oct. 9, 2019 by Teachoo

Transcript

Question 20 Find the value(s) of k for which the quadratic equation x2 + 2β2 ππ₯ + 18 = 0 has equal roots x2 + 2β2 ππ₯ + 18 = 0 Comparing equation with ax2 + bx + c = 0 a = 1, b = 2β2k , c = 18 Since the equation has 2 equal roots, D = 0 b2 β 4ac = 0 Putting values (2β2k)2 β 4 Γ 1 Γ 18 = 0 22 Γ (β2)^2Γ k2 β 72 = 0 4 Γ 2 Γ k2 = 72 8k2 = 72 k2 = 72/8 k2 = 9 k = Β± β9 k = Β± 3

CBSE Class 10 Sample Paper for 2020 Boards - Maths Standard

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Question 12 (OR 1st question)

Question 12 (OR 2ndΒ question)

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Question 18 (OR 1st question) Important

Question 18 (OR 2nd question) Important

Question 19

Question 20 You are here

Question 21 Important

Question 22 Important

Question 23 (OR 1st question) Important

Question 23 (OR 2nd question)

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Question 27 (OR 1st question)

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Question 29 (OR 1st question)

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Question 32 (OR 1st question) Important

Question 32 (OR 2nd question) Important

Question 33 Important

Question 34 Important

Question 35 (OR 1st question) Important

Question 35 (OR 2nd question)

Question 36

Question 37 (OR 1st question)

Question 37 (OR 2nd question)

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.