## Find the value(s) of k for which the quadratic equation

##
x
^{
2
}
+ 2√2 kx + 18 = 0 has equal roots

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Last updated at Nov. 1, 2019 by Teachoo

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Transcript

Question 20 Find the value(s) of k for which the quadratic equation x2 + 2β2 ππ₯ + 18 = 0 has equal roots x2 + 2β2 ππ₯ + 18 = 0 Comparing equation with ax2 + bx + c = 0 a = 1, b = 2β2k , c = 18 Since the equation has 2 equal roots, D = 0 b2 β 4ac = 0 Putting values (2β2k)2 β 4 Γ 1 Γ 18 = 0 22 Γ (β2)^2Γ k2 β 72 = 0 4 Γ 2 Γ k2 = 72 8k2 = 72 k2 = 72/8 k2 = 9 k = Β± β9 k = Β± 3

CBSE Class 10 Sample Paper for 2020 Boards - Maths Standard

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Class 10

Solutions of Sample Papers for Class 10 Boards

- CBSE Class 10 Sample Paper for 2021 Boards - Maths Standard
- CBSE Class 10 Sample Paper for 2021 Boards - Maths Basic
- CBSE Class 10 Sample Paper for 2020 Boards - Maths Standard
- CBSE Class 10 Sample Paper for 2020 Boards - Maths Basic
- CBSE Class 10 Sample Paper for 2019 Boards
- CBSE Class 10 Sample Paper for 2018 Boards

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.