The point which divides the line segment joining the points (8, – 9) and (2, 3) in ratio 1 : 2 internally lies in the
(a) I quadrant (b) II quadrant
(c) III quadrant (d) IV quadrant
Last updated at Nov. 1, 2019 by Teachoo
Transcript
Question 8 The point which divides the line segment joining the points (8, – 9) and (2, 3) in ratio 1 : 2 internally lies in the (a) I quadrant (b) II quadrant (c) III quadrant (d) IV quadrant Let points be A (8, –9) and B (2, 3) Let point be P(x, y) divide AB in ratio 1 : 2 Coordinates of P = ((𝑚_1 𝑥_2 + 𝑚_2 𝑥_1)/(𝑚_1 + 𝑚_2 ), (𝑚_1 𝑦_2 + 𝑚_2 𝑦_1)/(𝑚_1 + 𝑚_2 )) = ((1 × 2 + 2 × 8)/(1 + 2), (1 × 3 + 2 × (−9))/(1 + 2)) = ((2 + 16)/3, (3 − 18)/3) = (18/3, (−15)/3) = (6, –5) Since x is positive, y is negative The point lies in 4th Quadrant So, the correct answer is option D
CBSE Class 10 Sample Paper for 2020 Boards - Maths Standard
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CBSE Class 10 Sample Paper for 2020 Boards - Maths Standard
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