Question 27 (OR 1st question) Given that √5 is irrational, prove that 2√5 − 3 is an irrational number.
We have to prove 2√5 – 3 is irrational
Let us assume the opposite,
i.e., 2√5 – 3 is rational
Hence, 2√5 – 3 can be written in the form 𝑎/𝑏
where a and b are co-prime and b ≠ 0
Hence, 2√5 – 3 = 𝑎/𝑏
2√5 = 𝑎/𝑏 + 3
2√5 = (𝑎 + 3𝑏)/𝑏
√5 = 1/2 × (𝑎 + 3𝑏)/𝑏
√5 = (𝑎 + 3𝑏)/2𝑏
Here, (𝑎 + 3𝑏)/2𝑏 is a rational number
But √5 is irrational
Since, Rational ≠ Irrational
This is a contradiction
∴ Our assumption is incorrect
Hence, 2√5 – 3 is irrational
Hence proved
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Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.
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