Evaluate ∫ |x 2 - 2x|  dx from 1 to 3

Evaluate Integral |x^2 - 2x| from 1 to 3 - Teachoo - CBSE Class 12 Sam

Question 30 - CBSE Class 12 Sample Paper for 2020 Boards - Part 2
Question 30 - CBSE Class 12 Sample Paper for 2020 Boards - Part 3

Note : - This is similar to Example 30 of NCERT – Chapter 7 Class 12

Check the answer here https://www.teachoo.com/4811/727/Example-30---Evaluate-integral--1----2--x3---x--dx/category/Examples/

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Transcript

Question 30 Evaluate ∫ 3 1 |š‘„^2āˆ’2š‘„| dx |š‘„^2āˆ’2š‘„|=|š‘„(š‘„āˆ’2)| =|š‘„| |š‘„āˆ’2| Thus, š‘„=0, š‘„=2 Since our integration is from 1 to 3, we ignore x = 0 ∓ |š‘„^2āˆ’2š‘„|= {(š‘„Ć—āˆ’(š‘„āˆ’2) š‘–š‘“ 1ā‰¤š‘„<2š‘„Ć—(š‘„āˆ’2) š‘–š‘“ 2ā‰¤š‘„<3)┤ |š‘„^2āˆ’2š‘„|= {(āˆ’(š‘„^2āˆ’2š‘„) š‘–š‘“ 1ā‰¤š‘„<2(š‘„^2āˆ’2š‘„) š‘–š‘“ 2ā‰¤š‘„<3)┤ Now, ∫_1^3 |š‘„^2āˆ’2š‘„| dx = āˆ’āˆ«_1^2ā–’(š‘„^2āˆ’2š‘„) š‘‘š‘„+∫_2^3ā–’(š‘„^2āˆ’2š‘„) š‘‘š‘„ = āˆ’āˆ«_1^2ā–’š‘„^2 š‘‘š‘„+∫_1^2ā–’2š‘„ š‘‘š‘„+∫_2^3ā–’š‘„^2 š‘‘š‘„āˆ’āˆ«_2^3ā–’2š‘„ š‘‘š‘„ = āˆ’āˆ«_1^2ā–’š‘„^2 š‘‘š‘„+∫_2^3ā–’š‘„^2 š‘‘š‘„+∫_1^2ā–’2š‘„ š‘‘š‘„āˆ’āˆ«_2^3ā–’2š‘„ š‘‘š‘„ = āˆ’[š‘„^3/3]_1^2+[š‘„^3/3]_2^3+[š‘„^2 ]_1^2āˆ’[š‘„^2 ]_2^3 = āˆ’[2^3/3āˆ’1^3/3]+[3^3/3āˆ’2^3/3]+[2^2āˆ’1^2 ]āˆ’[3^2āˆ’2^2 ] = āˆ’[8/3āˆ’1/3]+[27/3āˆ’8/3]+[4āˆ’1]āˆ’[9āˆ’4] = āˆ’[7/3]+[19/3]+[3]āˆ’[5] = 12/3āˆ’2 = 4āˆ’2 = 2

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