CBSE Class 12 Sample Paper for 2020 Boards

Class 12
Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

## (d) 1/30 log ((3 + 5x)/(3 -5x)) + c

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Note : - This is same as Ex 7.4, 4 of NCERT β Chapter 7 Class 12

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### Transcript

Question 8 β« ππ₯/β(9 β 25π₯^2 ) (a) sin-1 (5π₯/3)+ c (b) 1/5 sin-1 (5π₯/3) + c (c) 1/6 log ((3 + 5π₯)/(3 β5π₯)) + c (d) 1/30 log ((3 + 5π₯)/(3 β5π₯)) + c β«1β1/β(9 β 25π₯^2 ) ππ₯ =β«1β1/β(25(9/25 β π₯^2 ) ) ππ₯ =β«1β1/(β25 β(9/25 β π₯^2 )) ππ₯ =1/5 β«1β1/β(9/25 β π₯^2 ) ππ₯ =1/5 β«1β1/β((3/5)^2 β π₯^2 ) ππ₯ It is of the form β«1βππ₯/β(π^2 β π₯^2 ) =γπ ππγ^(β1)β‘γπ₯/πγ +π β΄ Replacing π by 3/5 , we get =1/5 [sin^(β1)β‘γπ₯/(3/5)γ +πΆ1] =π/π γπππγ^(βπ)β‘γππ/πγ +πͺ So, (b) is the correct answer