If (2i + 6j + 27k ) Γ (i + pj + qk ) = 0 , then the values of p and q are?
(a) p = 6, q = 27Β Β Β Β Β Β Β Β Β (b) p = 3, q = 27/2Β Β
(c) p = 6, q = 27/2Β Β Β Β Β Β Β Β (d) p = 3,Β q = 27
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CBSE Class 12 Sample Paper for 2020 Boards
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CBSE Class 12 Sample Paper for 2020 Boards
Last updated at March 23, 2023 by Teachoo
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Question 3 If (2π Μ + 6π Μ + 27π Μ ) Γ (π Μ + pπ Μ + qπ Μ) = 0 β , then the values of p and q are? (a) p = 6, q = 27 (b) p = 3, q = 27/2 (c) p = 6, q = 27/2 (d) p = 3, q = 27 Given (2π Μ + 6π Μ + 27π Μ ) Γ (π Μ + pπ Μ + qπ Μ) = 0 β Therefore, |β 8(π Μ&π Μ&π Μ@2&6&[email protected]&π&π)|=0π Μ+0π Μ+0π Μ π Μ(6q β 27p) β π Μ(2q β 27) + π Μ(2p β 6) = 0π Μ+0π Μ+0π Μ Comparing 6q β 27p = 0 2q β 27 = 0 2q = 27 q = 27/2 2p β 6 = 0 2p = 6 p = 6/2 = 3 Therefore, p = 3, q = ππ/π So, (b) is the correct answer