If (2i + 6j + 27k ) Ɨ (i + pj + qk ) = 0 , then the values of p and q are?

(a) p = 6, q = 27Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  (b) p = 3, q = 27/2Ā Ā 

(c) p = 6, q = 27/2Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā (d) p = 3,Ā  q = 27

If (2i + 6j + 27k ) x (i + pj + qk ) = 0 , then the values of p and q

Question 3 - CBSE Class 12 Sample Paper for 2020 Boards - Part 2

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Question 3 If (2š‘– Ģ‚ + 6š‘— Ģ‚ + 27š‘˜ Ģ‚ ) Ɨ (š‘– Ģ‚ + pš‘— Ģ‚ + qš‘˜ Ģ‚) = 0 āƒ— , then the values of p and q are? (a) p = 6, q = 27 (b) p = 3, q = 27/2 (c) p = 6, q = 27/2 (d) p = 3, q = 27 Given (2š‘– Ģ‚ + 6š‘— Ģ‚ + 27š‘˜ Ģ‚ ) Ɨ (š‘– Ģ‚ + pš‘— Ģ‚ + qš‘˜ Ģ‚) = 0 āƒ— Therefore, |ā– 8(š‘– Ģ‚&š‘— Ģ‚&š‘˜ Ģ‚@2&6&27@1&š‘&š‘ž)|=0š‘– Ģ‚+0š‘— Ģ‚+0š‘˜ Ģ‚ š‘– Ģ‚(6q – 27p) – š‘— Ģ‚(2q – 27) + š‘˜ Ģ‚(2p – 6) = 0š‘– Ģ‚+0š‘— Ģ‚+0š‘˜ Ģ‚ Comparing 6q – 27p = 0 2q – 27 = 0 2q = 27 q = 27/2 2p – 6 = 0 2p = 6 p = 6/2 = 3 Therefore, p = 3, q = šŸšŸ•/šŸ So, (b) is the correct answer

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