If (2i + 6j + 27k ) × (i + pj + qk ) = 0 , then the values of p and q are?
(a) p = 6, q = 27 (b) p = 3, q = 27/2
(c) p = 6, q = 27/2 (d) p = 3, q = 27
Last updated at Oct. 17, 2019 by Teachoo
Transcript
Question 3 If (2๐ ฬ + 6๐ ฬ + 27๐ ฬ ) ร (๐ ฬ + p๐ ฬ + q๐ ฬ) = 0 โ , then the values of p and q are? (a) p = 6, q = 27 (b) p = 3, q = 27/2 (c) p = 6, q = 27/2 (d) p = 3, q = 27 Given (2๐ ฬ + 6๐ ฬ + 27๐ ฬ ) ร (๐ ฬ + p๐ ฬ + q๐ ฬ) = 0 โ Therefore, |โ 8(๐ ฬ&๐ ฬ&๐ ฬ@2&6&27@1&๐&๐)|=0๐ ฬ+0๐ ฬ+0๐ ฬ ๐ ฬ(6q โ 27p) โ ๐ ฬ(2q โ 27) + ๐ ฬ(2p โ 6) = 0๐ ฬ+0๐ ฬ+0๐ ฬ Comparing 6q โ 27p = 0 2q โ 27 = 0 2q = 27 q = 27/2 2p โ 6 = 0 2p = 6 p = 6/2 = 3 Therefore, p = 3, q = ๐๐/๐ So, (b) is the correct answer
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CBSE Class 12 Sample Paper for 2020 Boards
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