Find ∫xe (1 + x^2)  dx.

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  1. Class 12
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Transcript

Question 19 Find โˆซ1 xe(1 + x2) dx. โˆซ1 xe(1 + x2) dx. Let t = 1 + x2 dt = 2x dx ๐‘‘๐‘ก/2 = x dx Putting value of t and dt in equation โˆซ ๐‘ฅ๐‘’^((1 + ๐‘ฅ^2)) ๐‘‘๐‘ฅ = โˆซ1 ๐‘’^๐‘ก ๐‘‘๐‘ก/2 = 1/2 โˆซ1 ๐‘’^๐‘ก ๐‘‘๐‘ก = 1/2 ๐‘’^๐‘ก+๐ถ Putting back t = (1 + x2) = ๐Ÿ/๐Ÿ ๐’†^((๐Ÿ + ๐’™^๐Ÿ))+๐‘ช

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.