If tangent to the curve y 2 + 3x āˆ’ 7 = 0 at the point (ā„Ž, k) is parallel to line x āˆ’ y = 4, then value of k is ______?

If tangent to the curve y^2 + 3x āˆ’ 7 = 0 at point (h, k) is parallel

Question 14 (OR 1st Question) - CBSE Class 12 Sample Paper for 2020 Boards - Part 2
Question 14 (OR 1st Question) - CBSE Class 12 Sample Paper for 2020 Boards - Part 3

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Question 14 (OR 1st Question) If tangent to the curve y2 + 3x āˆ’ 7 = 0 at the point (ā„Ž, k) is parallel to line x āˆ’ y = 4, then value of k is ______? We know that Slope of tangent is š‘‘š‘¦/š‘‘š‘„ Now, y2 + 3x āˆ’ 7 = 0 Differentiating w.r.t.š‘„ 2yš‘‘š‘¦/š‘‘š‘„ + 3 – 0 = 0 2yš‘‘š‘¦/š‘‘š‘„ + 3 = 0 2yš‘‘š‘¦/š‘‘š‘„ = –3 š‘‘š‘¦/š‘‘š‘„ = (āˆ’3)/2š‘¦ At point (h, k) Slope is š‘‘š‘¦/š‘‘š‘„ = (āˆ’3)/2š‘˜ Now, finding slope of line x āˆ’ y = 4 x āˆ’ y = 4 x – 4 = y y = x – 4 Comparing with y = mx + c So, slope of line is 1 Since tangent and line are parallel Slope of tangent = 1 š‘‘š‘¦/š‘‘š‘„ = 1 (āˆ’3)/2š‘˜ = 1 –3 = 2k (āˆ’3)/2 = k k = (āˆ’šŸ‘)/šŸ

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