Last updated at Dec. 16, 2024 by Teachoo
Misc 2 (Introduction) Find the equation of a line parallel to x-axis and passing through the origin.Direction cosines of a line making angle ๐ผ with x -axis, ๐ฝ with y โ axis and ๐พ with z โ axis are l, m, n l = cos ๐ผ , m = cos ๐ฝ , n = cos ๐พ x โ axis makes an angle 0ยฐ with x โ axis, 90ยฐ with y โ axis & 90ยฐ with z โ axis. So, ๐ถ = 0ยฐ, ๐ท = 90ยฐ, ๐ธ = 90ยฐ Direction cosines are l = cos 0ยฐ , m = cos 90ยฐ , n = cos 90ยฐ l = 1 , m = 0, n = 0 โด Direction cosines of x โ axis are 1, 0, 0. Misc 2 Find the equation of a line parallel to x-axis and passing through the origin.Equation of a line passing through (x1, y1, z1) and parallel to a line with direction ratios a, b, c is (๐ โ ๐๐)/๐ = (๐ โ ๐๐)/๐ = (๐ โ ๐๐)/๐ Since line passes through origin ie. (0, 0, 0), x1 = 0, y1 = 0, z1 = 0 Since line is parallel to x โ axis, ๐ = 1, b = 0, c = 0 Equation of line is (๐ฅ โ 0)/1 = (๐ฆ โ 0)/0 = (๐ง โ 0)/0 ๐/๐ = ๐/๐ = ๐/๐
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo