Example 6 - Chapter 4 Class 12 Determinants
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Example 6 Find the area of the triangle whose vertices are (3, 8), (– 4, 2) and (5, 1). The area of triangle is given by ∆ = 1/2 |■8(x1&y1&1@x2&y2&1@x3&y3&1)| Here x1 = 3 , y1 = 8, x2 = – 4 , y2 = 2, x3 = 5 , y3 = 1 ∆ = 1/2 |■8(3&8&1@−4&2&1@5&1&1)| = 1/2 (3|■8(2&1@1&1)|−8|■8(−4&1@5&1)|+1|■8(−4&2@5&1)|) = 1/2 (3( 2 – 1) – 8 ( – 4 – 5) + 1 ( – 4 – 10) ) = 1/2 (3 (1) – 8 ( – 9) + 1 ( – 14)) = 1/2 (3 + 72 – 14) = 61/2 Thus, the required area of triangle is 𝟔𝟏/𝟐 square units
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo