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Question 4 Evaluate |■8(102&18&36@1&3&4@17&3&6)| ∆ = |■8(102&18&36@1&3&4@17&3&6)| ∆ = |■8(𝟔(17)&𝟔(3)&𝟔(6)@1&3&4@17&3&6)| Here 1st row is multiplied by 6 So, ∆ = 6 |■8(𝟏𝟕&𝟑&𝟔@1&3&4@𝟏𝟕&𝟑&𝟔)| Property: If each element of row of determinant is multiplied by a constant k , then its value get multiplied by k Since Row 1 & Row 3 are identical = 6 × (0) = 0 Hence, ∆ = 0 Property: If any two rows & columns of determinants are identical , then value of determinant is 0.

  1. Chapter 4 Class 12 Determinants
  2. Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo