Example 5 - Chapter 4 Class 12 Determinants
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Example 5 Find values of x for which |■8(3&x@x&1)| = |■8(3&2@4&1)| Given |■8(3&x@x&1)| = |■8(3&2@4&1)| Putting values 3 – x2 = – 5 – x2 = – 5 – 3 – x2 = – 8 x2 = 8 Calculating |■8(3&x@x&1)| = 3(1) – x (x) = 3 – x2 Calculating |■8(3&2@4&1)| = 3(1) – 4(2) = 3 – 8 = – 5 x = ± √8 = ± √(2" ×" 2" ×" 2) = ± 2√2 Hence value of x is ± 2√𝟐
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo