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Transcript

Misc 1 Find the area under the given curves and given lines: (ii) ๐‘ฆ= ๐‘ฅ4, ๐‘ฅ = 1, ๐‘ฅ = 5 and ๐‘ฅ-axisArea required = Area ABCD = โˆซ_1^5โ–’ใ€–๐‘ฆ ๐‘‘๐‘ฅใ€— y โ†’ Equation of curve ๐‘ฆ=๐‘ฅ^2 Thus, Area required = โˆซ_1^5โ–’ใ€–๐‘ฆ ๐‘‘๐‘ฅใ€— =โˆซ_๐Ÿ^๐Ÿ“โ–’ใ€–๐’™^๐Ÿ’ ๐’…๐’™ใ€— =[๐‘ฅ^5/5]_1^5 =5^5/5โˆ’1^5/5 =5^4โˆ’1/5 = 625 โ€“ 0.2 = 624.8 square units

  1. Chapter 8 Class 12 Application of Integrals
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo