Misc 1 (ii) - Chapter 8 Class 12 Application of Integrals
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Misc 1 Find the area under the given curves and given lines: (ii) ๐ฆ= ๐ฅ4, ๐ฅ = 1, ๐ฅ = 5 and ๐ฅ-axisArea required = Area ABCD = โซ_1^5โใ๐ฆ ๐๐ฅใ y โ Equation of curve ๐ฆ=๐ฅ^2 Thus, Area required = โซ_1^5โใ๐ฆ ๐๐ฅใ =โซ_๐^๐โใ๐^๐ ๐ ๐ใ =[๐ฅ^5/5]_1^5 =5^5/5โ1^5/5 =5^4โ1/5 = 625 โ 0.2 = 624.8 square units
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo