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Ex 6.1, 4 - Chapter 6 Class 8 Cubes and Cube Roots
Last updated at July 21, 2023 by Teachoo
Ex 6.1
Ex 6.1, 1 (i)
Ex 6.1, 1 (ii)
Ex 6.1, 1 (iii) Important
Ex 6.1, 1 (iv)
Ex 6.1, 1 (v) Important
Ex 6.1, 2 (i)
Ex 6.1, 2 (ii) Important
Ex 6.1, 2 (iii)
Ex 6.1, 2 (iv) Important
Ex 6.1, 2 (v)
Ex 6.1, 3 (i) Important
Ex 6.1, 3 (ii)
Ex 6.1, 3 (iii)
Ex 6.1, 3 (iv) Important
Ex 6.1, 3 (v)
Ex 6.1, 4 Important You are here
Transcript
Ex 6.1, 4 Parikshit makes a cuboid of plasticine of sides 5 cm, 2 cm, 5 cm. How many such cuboids will he need to form a cube? Here cuboids are joined to form a cube. So, Volume of cuboid × Number of cuboids = Volume of cube Volume of Cuboid Sides are 5, 2, 5 cm Length = 5 cm Breadth = 2 cm Height = 5 cm Volume = Length × Breadth × Height = 5 × 2 × 5 Volume of Cube Let side of cube = a Volume = Side3 = a3 Now, Volume of cuboid × Number of cuboids = Volume of cube 5 × 2 × 5 × Number of cuboids = a3 a3 = 5 × 2 × 5 × Number of cuboids Since on the left we have cube, we should have cube on the right as well To form cube on the right We multiply by 5 × 2 × 2 Thus, in a3 = 5 × 2 × 5 × Number of cuboids Putting Number of cuboids = 5 × 2 × 2 a3 = 5 × 2 × 5 × 5 × 2 × 2 a3 = 5 × 5 × 5 × 2 × 2 × 2 Therefore, Number of cuboids = 5 × 2 × 2 = 20
