Ex 6.1, 3 (iii) - Chapter 6 Class 8 Cubes and Cube Roots

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Ex 6.1, 3 Find the smallest number by which each of the following numbers must be divided to obtain a perfect cube. (iii) 135 We see that 135 = 3 × 3 × 3 × 5 Since 5 does not occur in triplets, ∴ 135 is not a perfect cube. So, we divide by 5 to make triplet So, our number becomes 135 × 𝟏/𝟓 = 3 × 3 × 3 × 5 × 𝟏/𝟓 = 3 × 3 × 3 Now, it becomes a perfect cube. So, we divide 135 by 5 to make it a perfect cube

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo