Ex 6.1, 3 (iii) - Chapter 6 Class 8 Cubes and Cube Roots
Last updated at April 16, 2024 by Teachoo
Ex 6.1
Ex 6.1, 1 (i)
Ex 6.1, 1 (ii)
Ex 6.1, 1 (iii) Important
Ex 6.1, 1 (iv)
Ex 6.1, 1 (v) Important
Ex 6.1, 2 (i)
Ex 6.1, 2 (ii) Important
Ex 6.1, 2 (iii)
Ex 6.1, 2 (iv) Important
Ex 6.1, 2 (v)
Ex 6.1, 3 (i) Important
Ex 6.1, 3 (ii)
Ex 6.1, 3 (iii) You are here
Ex 6.1, 3 (iv) Important
Ex 6.1, 3 (v)
Ex 6.1, 4 Important
Transcript
Ex 6.1, 3 Find the smallest number by which each of the following numbers must be divided to obtain a perfect cube. (iii) 135 We see that 135 = 3 × 3 × 3 × 5 Since 5 does not occur in triplets, ∴ 135 is not a perfect cube. So, we divide by 5 to make triplet So, our number becomes 135 × 𝟏/𝟓 = 3 × 3 × 3 × 5 × 𝟏/𝟓 = 3 × 3 × 3 Now, it becomes a perfect cube. So, we divide 135 by 5 to make it a perfect cube
