Ex 7.1, 2 (i) - Chapter 7 Class 8 Cubes and Cube Roots
Last updated at Sept. 1, 2021 by Teachoo
Ex 7.1
Ex 7.1, 1 (i)
Ex 7.1, 1 (ii)
Ex 7.1, 1 (iii) Important
Ex 7.1, 1 (iv)
Ex 7.1, 1 (v) Important
Ex 7.1, 2 (i) You are here
Ex 7.1, 2 (ii) Important
Ex 7.1, 2 (iii)
Ex 7.1, 2 (iv) Important
Ex 7.1, 2 (v)
Ex 7.1, 3 (i) Important
Ex 7.1, 3 (ii)
Ex 7.1, 3 (iii)
Ex 7.1, 3 (iv) Important
Ex 7.1, 3 (v)
Ex 7.1, 4 Important
Transcript
Ex 7.1, 2 Find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube. (i) 243 We see that 243 = 3 × 3 × 3 × 3 × 3 Since 3 does not occur in triplets, ∴ 243 is not a perfect cube. So, we multiply by 3 to make triplet So, our number becomes 243 × 3 = 3 × 3 × 3 × 3 × 3 × 3 Now, it becomes a perfect cube. So, we multiply 243 by 3 to make it a perfect cube
