# Ex 7.1, 2 - Chapter 7 Class 8 Cubes and Cube Roots

Last updated at Sept. 11, 2018 by Teachoo

Last updated at Sept. 11, 2018 by Teachoo

Transcript

Ex 7.1, 2 Find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube. (i) 243 We see that 243 = 3 × 3 × 3 × 3 × 3 Since 3 does not occur in triplets, ∴ 243 is not a perfect cube. So, we multiply by 3 to make triplet So, our number becomes 243 × 3 = 3 × 3 × 3 × 3 × 3 × 3 Now, it becomes a perfect cube. So, we multiply 243 by 3 to make it a perfect cube Ex 7.1, 2 Find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube. (ii) 256 We see that 256 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 Since 2 does not occur in triplets, ∴ 256 is not a perfect cube. So, we multiply by 2 to make triplet So, our number becomes 256 × 2 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 Now, it becomes a perfect cube. So, we multiply 256 by 2 to make it a perfect cube Ex 7.1, 2 Find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube. (iii) 72 We see that 72 = 2 × 2 × 2 × 3 × 3 Since 3 does not occur in triplets, ∴ 72 is not a perfect cube. So, we multiply by 3 to make triplet So, our number becomes 72 × 3 = 2 × 2 × 2 × 3 × 3 × 3 Now, it becomes a perfect cube. So, we multiply 72 by 3 to make it a perfect cube Ex 7.1, 2 Find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube. (iv) 675 We see that 675 = 3 × 3 × 3 × 5 × 5 Since 5 does not occur in triplets, ∴ 675 is not a perfect cube. So, we multiply by 5 to make triplet So, our number becomes 675 × 5 = 3 × 3 × 3 × 5 × 5 × 5 Now, it becomes a perfect cube. So, we multiply 675 by 5 to make it a perfect cube Ex 7.1, 2 Find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube. (v) 100 We see that 100 = 2 × 2 × 5 × 5 Since 2 & 5 does not occur in triplets, ∴ 100 is not a perfect cube. So, we multiply by 2 × 5 to make triplet So, our number becomes 100 × 2 × 5 = 2 × 2 × 5 × 5 × 2 × 5 = 2 × 2 × 2 × 5 × 5 × 5 Now, it becomes a perfect cube. So, we multiply 100 by 2 × 5 i.e. 10 to make it a perfect cube

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.