Ex 6.1, 2 (i) - Chapter 6 Class 8 Cubes and Cube Roots
Last updated at Dec. 16, 2024 by Teachoo
Ex 6.1
Ex 6.1, 1 (i)
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Transcript
Ex 6.1, 2 Find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube. (i) 243 We see that 243 = 3 × 3 × 3 × 3 × 3 Since 3 does not occur in triplets, ∴ 243 is not a perfect cube. So, we multiply by 3 to make triplet So, our number becomes 243 × 3 = 3 × 3 × 3 × 3 × 3 × 3 Now, it becomes a perfect cube. So, we multiply 243 by 3 to make it a perfect cube
