Ex 7.1, 2 - Find the smallest number by which each of the numbers

Ex 7.1, 2 - Chapter 7 Class 8 Cubes and Cube Roots - Part 2

 

  1. Chapter 7 Class 8 Cubes and Cube Roots
  2. Serial order wise

Transcript

Ex 7.1, 2 Find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube. (i) 243 We see that 243 = 3 × 3 × 3 × 3 × 3 Since 3 does not occur in triplets, ∴ 243 is not a perfect cube. So, we multiply by 3 to make triplet So, our number becomes 243 × 3 = 3 × 3 × 3 × 3 × 3 × 3 Now, it becomes a perfect cube. So, we multiply 243 by 3 to make it a perfect cube

About the Author

Davneet Singh's photo - Teacher, Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.