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Ex 6.1, 2 Find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube. (v) 100 We see that 100 = 2 × 2 × 5 × 5 Since 2 & 5 does not occur in triplets, ∴ 100 is not a perfect cube. So, we multiply by 2 × 5 to make triplet So, our number becomes 100 × 2 × 5 = 2 × 2 × 5 × 5 × 2 × 5 = 2 × 2 × 2 × 5 × 5 × 5 Now, it becomes a perfect cube. So, we multiply 100 by 2 × 5 i.e. 10 to make it a perfect cube

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.