Ex 7.1, 3 - Chapter 7 Class 8 Cubes and Cube Roots - Part 7

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Ex 7.1, 3 - Chapter 7 Class 8 Cubes and Cube Roots - Part 8

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  1. Chapter 7 Class 8 Cubes and Cube Roots
  2. Serial order wise

Transcript

Ex 7.1, 3 Find the smallest number by which each of the following numbers must be divided to obtain a perfect cube. (iv) 192We see that 192 = 2 × 2 × 2 × 2 × 2 × 2 × 3 Since 3 does not occur in triplets, ∴ 192 is not a perfect cube. So, we divide by 3 to make triplet So, our number becomes 192 × 𝟏/𝟑 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 𝟏/𝟑 = 2 × 2 × 2 × 2 × 2 × 2 Now, it becomes a perfect cube. So, we divide 192 by 3 to make it a perfect cube

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.