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Ex 6.1, 3 (iv) - Chapter 6 Class 8 Cubes and Cube Roots
Last updated at July 21, 2023 by Teachoo
Ex 6.1
Ex 6.1, 1 (i)
Ex 6.1, 1 (ii)
Ex 6.1, 1 (iii) Important
Ex 6.1, 1 (iv)
Ex 6.1, 1 (v) Important
Ex 6.1, 2 (i)
Ex 6.1, 2 (ii) Important
Ex 6.1, 2 (iii)
Ex 6.1, 2 (iv) Important
Ex 6.1, 2 (v)
Ex 6.1, 3 (i) Important
Ex 6.1, 3 (ii)
Ex 6.1, 3 (iii)
Ex 6.1, 3 (iv) Important You are here
Ex 6.1, 3 (v)
Ex 6.1, 4 Important
Transcript
Ex 6.1, 3 Find the smallest number by which each of the following numbers must be divided to obtain a perfect cube. (iv) 192We see that 192 = 2 × 2 × 2 × 2 × 2 × 2 × 3 Since 3 does not occur in triplets, ∴ 192 is not a perfect cube. So, we divide by 3 to make triplet So, our number becomes 192 × 𝟏/𝟑 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 𝟏/𝟑 = 2 × 2 × 2 × 2 × 2 × 2 Now, it becomes a perfect cube. So, we divide 192 by 3 to make it a perfect cube
