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Ex 6.1, 2 (iii) - Chapter 6 Class 8 Cubes and Cube Roots
Last updated at July 21, 2023 by Teachoo
Ex 6.1
Ex 6.1, 1 (i)
Ex 6.1, 1 (ii)
Ex 6.1, 1 (iii) Important
Ex 6.1, 1 (iv)
Ex 6.1, 1 (v) Important
Ex 6.1, 2 (i)
Ex 6.1, 2 (ii) Important
Ex 6.1, 2 (iii) You are here
Ex 6.1, 2 (iv) Important
Ex 6.1, 2 (v)
Ex 6.1, 3 (i) Important
Ex 6.1, 3 (ii)
Ex 6.1, 3 (iii)
Ex 6.1, 3 (iv) Important
Ex 6.1, 3 (v)
Ex 6.1, 4 Important
Transcript
Ex 6.1, 2 Find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube. (iii) 72 We see that 72 = 2 × 2 × 2 × 3 × 3 Since 3 does not occur in triplets, ∴ 72 is not a perfect cube. So, we multiply by 3 to make triplet So, our number becomes 72 × 3 = 2 × 2 × 2 × 3 × 3 × 3 Now, it becomes a perfect cube. So, we multiply 72 by 3 to make it a perfect cube
