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Ex 7.1, 3 - Chapter 7 Class 8 Cubes and Cube Roots - Part 3

Ex 7.1, 3 - Chapter 7 Class 8 Cubes and Cube Roots - Part 4


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Ex 7.1, 3 Find the smallest number by which each of the following numbers must be divided to obtain a perfect cube. (ii) 128We see that 128 = 2 × 2 × 2 × 2 × 2 × 2 × 2 Since 2 does not occur in triplets, ∴ 128 is not a perfect cube. So, we divide by 2 to make triplet So, our number becomes 128 × 𝟏/𝟐 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 𝟏/𝟐 = 2 × 2 × 2 × 2 × 2 × 2 Now, it becomes a perfect cube. So, we divide 128 by 2 to make it a perfect cube

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.