Ex 6.1
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Last updated at Dec. 16, 2024 by Teachoo
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Ex 6.1, 3 Find the smallest number by which each of the following numbers must be divided to obtain a perfect cube. (ii) 128We see that 128 = 2 × 2 × 2 × 2 × 2 × 2 × 2 Since 2 does not occur in triplets, ∴ 128 is not a perfect cube. So, we divide by 2 to make triplet So, our number becomes 128 × 𝟏/𝟐 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 𝟏/𝟐 = 2 × 2 × 2 × 2 × 2 × 2 Now, it becomes a perfect cube. So, we divide 128 by 2 to make it a perfect cube
