Ex 6.1
Ex 6.1, 1 (ii)
Ex 6.1, 1 (iii) Important
Ex 6.1, 1 (iv)
Ex 6.1, 1 (v) Important
Ex 6.1, 2 (i)
Ex 6.1, 2 (ii) Important
Ex 6.1, 2 (iii)
Ex 6.1, 2 (iv) Important
Ex 6.1, 2 (v)
Ex 6.1, 3 (i) Important
Ex 6.1, 3 (ii) You are here
Ex 6.1, 3 (iii)
Ex 6.1, 3 (iv) Important
Ex 6.1, 3 (v)
Ex 6.1, 4 Important
Last updated at April 16, 2024 by Teachoo
Ex 6.1, 3 Find the smallest number by which each of the following numbers must be divided to obtain a perfect cube. (ii) 128We see that 128 = 2 × 2 × 2 × 2 × 2 × 2 × 2 Since 2 does not occur in triplets, ∴ 128 is not a perfect cube. So, we divide by 2 to make triplet So, our number becomes 128 × 𝟏/𝟐 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 𝟏/𝟐 = 2 × 2 × 2 × 2 × 2 × 2 Now, it becomes a perfect cube. So, we divide 128 by 2 to make it a perfect cube