Example 3 - Chapter 2 Class 8 Linear Equations in One Variable

Last updated at Dec. 16, 2024 by

Example 3 - Solve 6x + 1/3 = x - 3/6 - Chapter 2 Class 8 - Teachoo - Examples

part 2 - Example 3 - Examples - Serial order wise - Chapter 2 Class 8 Linear Equations in One Variable

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Example 3 Solve (6𝑥 + 1)/3+1=(𝑥 − 3)/6 (6𝑥 + 1)/3+1=(𝑥 − 3)/6 (6𝑥 + 1 + 1 × 3)/3=(𝑥 − 3)/6 (𝟔 𝒙 + 𝟒)/𝟑=(𝒙 − 𝟑)/𝟔 6 (6x + 4) = 3 (x − 3) 36x + 24 = 3 (x − 3) 36x + 24 = 3x − 9 36x − 3x + 24 = −9 33x + 24 = −9 33x = − 9 − 24 33x = −33 L.H.S (6𝑥 + 1)/3+1 = (6(−1) + 1 )/3+1 = (−6 + 1 )/3+1 = −5/3+1 = (−5 + 3)/3 = (−2)/3 x = (−33)/33=−𝟏 Check: ∴ LHS = RHS Hence Verified. R.H.S (𝑥 − 3)/6 = ((−1) − 3)/6 = (−4)/6 = (−2)/3

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo