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Ex 2.6, 1 - Chapter 2 Class 8 Linear Equations in One Variable
Last updated at June 21, 2018 by Teachoo
Transcript
Ex 2.6, 1 Solve the following equations. (8π₯ β 3)/3π₯=2 (8π₯ β 3)/3π₯=2 8π₯ β 3 = 2 Γ 3π₯ 8π₯ β 3 = 6π₯ 8π₯ = 6π₯+ 3 8π₯β6π₯ = 3 2π₯ = 3 π=π/π Check:- Solving L.H.S (8π₯ β 3)/3π₯ =(8 Γ 3/2 β 3)/(3 Γ 3/2) =((24 β 6)/2)/(9/2)=(18/2)/(9/2)=18/2Γ2/9=2 = RHS β΄ LHS = RHS Hence Verified.
