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  1. Chapter 2 Class 8 Linear Equations in One Variable
  2. Serial order wise
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Ex 2.6, 4 Solve the following equations. (3 + 4)/(2 6 )= ( 2)/5 (3 + 4)/(2 6 )= ( 2)/5 5 (3y + 4) = 2 (2 6y) 15y + 20 = 2(2 6y) 15y + 20 = 4 + 12y 15y 12y + 20 = 4 3y + 20 = 4 3y = 4 20 3y = 24 y = ( 24)/3 y = 8 Check:- L.H.S = (3 + 4)/(2 6 ) =(3( 8) + 4)/(2 6( 8))=( 24 + 4)/(2 + 48)=( 20)/50 =( 2)/5 = R.H.S LHS = RHS Hence Verified.

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.