Chapter 2 Class 8 Linear Equations in One Variable
Serial order wise

Question 4 - Solving difficult equations - Word Problems - Chapter 2 Class 8 Linear Equations in One Variable

Last updated at Dec. 16, 2024 by

Ex 2.6, 4 - Solve 3y + 4/ 2 - 6y = -2/5 - Chapter 2 Class 8 NCERT

Ex 2.6, 4 - Chapter 2 Class 8 Linear Equations in One Variable - Part 2

Something went wrong!

The video couldn't load due to a technical hiccup.
But don't worry — our team is already on it, and we're working hard to get it back up ASAP.

Thanks for bearing with us!

Share on WhatsApp

Transcript

Question 4 Solve the following equations. (3 + 4)/(2 6 )= ( 2)/5 (3 + 4)/(2 6 )= ( 2)/5 5 (3y + 4) = 2 (2 6y) 15y + 20 = 2(2 6y) 15y + 20 = 4 + 12y 15y 12y + 20 = 4 3y + 20 = 4 3y = 4 20 3y = 24 y = ( 24)/3 y = 8 Check:- L.H.S = (3 + 4)/(2 6 ) =(3( 8) + 4)/(2 6( 8))=( 24 + 4)/(2 + 48)=( 20)/50 =( 2)/5 = R.H.S LHS = RHS Hence Verified.

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo