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  1. Chapter 2 Class 8 Linear Equations in One Variable
  2. Serial order wise
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Ex 2.6, 5 Solve the following equations. (7๐‘ฆ + 4)/(๐‘ฆ + 2)=(โˆ’4)/3 (7๐‘ฆ + 4)/(๐‘ฆ + 2)=(โˆ’4)/3 3 (7y + 4) = โˆ’4 (y + 2) 21y + 12 = โˆ’4 (y + 2) 21y + 12 = โˆ’4y โˆ’ 8 21y + 4y + 12 = โˆ’8 25y + 12 = โˆ’8 25y = โˆ’8 โˆ’ 12 25y = โˆ’20 y = (โˆ’20)/25 y = (โˆ’๐Ÿ’)/๐Ÿ“ Check:- L.H.S = (7๐‘ฆ + 4)/(๐‘ฆ + 2) =(7 ((โˆ’4)/5) + 4)/((โˆ’4)/5 + 2)=((โˆ’28)/5 + 4)/((โˆ’4)/5 + 2) = ((โˆ’28 + 4(5))/5)/((โˆ’4 + 2(5))/5) = ((โˆ’28 + 20)/5)/((โˆ’4 + 10)/5)=((โˆ’8)/5)/(6/5)=(โˆ’8)/5ร—5/6 =(โˆ’4)/3= R.H.S โˆด LHS = RHS Hence Verified.

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.