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Question 5 - Solving difficult equations - Word Problems - Chapter 2 Class 8 Linear Equations in One Variable
Last updated at Dec. 16, 2024 by Teachoo
Solving difficult equations - Word Problems
Chapter 2 Class 8 Linear Equations in One Variable
Serial order wise
- Ex 2.1
- Ex 2.2
- Examples
- Solving easy equations
- Solving easy equations - Word Problems
- Solving difficult equations
-
Solving difficult equations - Word Problems
Transcript
Question 5 Solve the following equations. (7𝑦 + 4)/(𝑦 + 2)=(−4)/3 (7𝑦 + 4)/(𝑦 + 2)=(−4)/3 3 (7y + 4) = −4 (y + 2) 21y + 12 = −4 (y + 2) 21y + 12 = −4y − 8 21y + 4y + 12 = −8 25y + 12 = −8 25y = −8 − 12 25y = −20 y = (−20)/25 y = (−𝟒)/𝟓 Check:- L.H.S = (7𝑦 + 4)/(𝑦 + 2) =(7 ((−4)/5) + 4)/((−4)/5 + 2)=((−28)/5 + 4)/((−4)/5 + 2) = ((−28 + 4(5))/5)/((−4 + 2(5))/5) = ((−28 + 20)/5)/((−4 + 10)/5)=((−8)/5)/(6/5)=(−8)/5×5/6 =(−4)/3= R.H.S ∴ LHS = RHS Hence Verified.
