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  1. Chapter 2 Class 8 Linear Equations in One Variable
  2. Serial order wise
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Ex 2.6, 3 Solve the following equations. š‘§/(š‘§ + 15)=4/99z = 4 (z + 15) 9z = 4z + 60 9z āˆ’ 4z = 60 5z = 60 z = 60/5 z = 12 Check:- L.H.S = š‘§/(š‘§ + 15) =12/(12 + 15)=12/27 =4/9 = R.H.S āˆ“ LHS = RHS Hence Verified.

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.