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Last updated at June 21, 2018 by Teachoo
Transcript
Ex 2.5, 1 Solve the following linear equations. π₯/2β1/5=π₯/3+1/4 π₯/2β1/5=π₯/3+1/4 (5π₯ β 2)/10=(4π₯ + 3)/12 12 (5x β 2) = 10 (4x + 3) 60x β 24 = 10 (4x + 3) 60x β 24 = 40x + 30 60x β 40x β 24 = 30 20x β 24 = 30 20x = 30 + 24 20x = 54 x = 54/20 x = ππ/ππ Check:- β΄ LHS = RHS Hence Verified. L.H.S π₯/2 β1/5 =27/10 Γ1/2β1/5=(27 β 4)/20=23/20 R.H.S π₯/3+ 1/4 =27/10Γ1/3+1/4=(54 + 15)/60=69/60=23/20
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