You are here
Ex 2.2, 9 - Chapter 2 Class 8 Linear Equations in One Variable
Last updated at Dec. 16, 2024 by Teachoo
Transcript
Ex 2.2, 9 Simplify and solve the following linear equations. 3(5z – 7) – 2(9z – 11) = 4(8z – 13) – 173(5z – 7) – 2(9z – 11) = 4(8z – 13) – 17 15z − 21 − 18z + 22 = 4 (8z − 13) − 17 15z − 18z + 22 − 21 = 4 (8z − 13) − 17 −3z + 1 = 4 (8z − 13) − 17 −3z + 1 = 32z − 52 − 17 −3z + 1 = 32z − 69 −3z = 32z − 70 −3z − 32z = −70 −35z = − 70 z = (−70)/(−35) z = 2 L.H.S 3 (5z − 7) − 2(9z − 11) = 3 (5 × 2 − 7) − 2(9 × 2 − 11) = 3 (10 − 7) − 2(18 − 11) = 3 × 3 − 2 × 7 = 9 − 14 = −5 R.H.S 4 (8z − 13) − 17 = 4 (8 × 2 − 13) − 17 = 4 (16 − 13) − 17 = 4 × 3 − 17 = 12 − 17 = −5 Check:- ∴ LHS = RHS Hence Verified.
