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  1. Chapter 2 Class 8 Linear Equations in One Variable
  2. Serial order wise
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Transcript

Ex 2.5, 6 Solve the following linear equations. π‘šβˆ’(π‘š βˆ’ 1)/2=1βˆ’(π‘š βˆ’ 2)/33m + 3 = 2 (5 βˆ’ m) 3m + 3 = 10 βˆ’ 2m 3m + 2m + 3 = 10 5m + 3 = 10 5m + 3 = 10 5m = 10 βˆ’ 3 5m = 7 m = πŸ•/πŸ“ Check:- L.H.S π‘šβˆ’(π‘š βˆ’ 1)/2 =7/5βˆ’(7/5 βˆ’ 1)/2 = 7/5βˆ’ ( (7 βˆ’ 5)/5 )/2=7/5βˆ’2/10 =7/5βˆ’1/5=6/5 R.H.S 1βˆ’(π‘š βˆ’ 2)/3 =1βˆ’(7/5 βˆ’ 2)/3 = 1βˆ’ ( (7 βˆ’ 2(5))/5 )/3= 1 – ((7 βˆ’ 10)/5)/3 = 1 – (βˆ’3/5)/3 = 1 + 3/15 =1+1/5=6/5 ∴ LHS = RHS Hence Verified.

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.