
Last updated at June 21, 2018 by Teachoo
Ex 2.5, 2 Solve the following linear equations. 𝑛/2−3𝑛/4+5𝑛/6=21 𝑛/2−3𝑛/4+5𝑛/6=21 (6𝑛 − 3(3𝑛) + 2(5𝑛))/12=21 (6𝑛 − 9𝑛 + 10𝑛)/12=21 (6𝑛 + 𝑛)/12=21 7𝑛/12=21 7n = 21 × 12 n = (21 × 12)/7 n = 36 L.H.S 𝑛/2− 3𝑛/4+5𝑛/6 =36/2 −(3 × 36)/4+(5 × 36)/6 =18−27+30 =21 = R.H.S ∴ LHS = RHS Hence Verified.