
Subscribe to our Youtube Channel - https://you.tube/teachoo
Last updated at June 21, 2018 by Teachoo
Transcript
Ex 2.5, 2 Solve the following linear equations. ๐/2โ3๐/4+5๐/6=21 ๐/2โ3๐/4+5๐/6=21 (6๐ โ 3(3๐) + 2(5๐))/12=21 (6๐ โ 9๐ + 10๐)/12=21 (6๐ + ๐)/12=21 7๐/12=21 7n = 21 ร 12 n = (21 ร 12)/7 n = 36 L.H.S ๐/2โ 3๐/4+5๐/6 =36/2 โ(3 ร 36)/4+(5 ร 36)/6 =18โ27+30 =21 = R.H.S โด LHS = RHS Hence Verified.
About the Author