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Ex 2.2, 5 - Chapter 2 Class 8 Linear Equations in One Variable
Last updated at July 6, 2023 by Teachoo
Transcript
Ex 2.2, 5 Solve the following linear equations. (3𝑡 − 2)/4−(2𝑡 + 3)/3=2/3−𝑡 (3𝑡 − 2)/4−(2𝑡 + 3)/3=2/3−𝑡 (𝟑(𝟑𝒕 − 𝟐) − 𝟒 (𝟐𝒕 + 𝟑))/𝟏𝟐=𝟐/𝟑−𝒕 (9𝑡 − 6 − 8𝑡 − 12)/12=2/3−𝑡 (9𝑡 − 8𝑡 − 6 − 12)/12=2/3−𝑡 (𝑡 − 18)/12=2/3−𝑡 (𝑡 − 18)/12=(2 − 3𝑡)/3 3 (t − 18) = 12 (2 − 3t) 3t − 54 = 24 − 36t 3t + 36t − 54 = 24 39t − 54 = 24 39t = 24 + 54 39t = 78 t = 78/39 t = 2 Check:- L.H.S (3𝑡 − 2)/4−(2𝑡 + 3)/3=(3(2) − 2)/4 −(2(2) + 3 )/3 = (6 − 2)/4−(4 + 3)/3=4/4− 7/3=1−7/3 = (3 − 7)/3=(−4)/3 R.H.S 2/3−𝑡 = 2/3−2=(2 − 6)/3=(−4)/3
