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  1. Chapter 2 Class 8 Linear Equations in One Variable
  2. Serial order wise
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Ex 2.5, 5 Solve the following linear equations. (3๐‘ก โˆ’ 2)/4โˆ’(2๐‘ก + 3)/3=2/3โˆ’๐‘ก (3๐‘ก โˆ’ 2)/4โˆ’(2๐‘ก + 3)/3=2/3โˆ’๐‘ก (3(3๐‘ก โˆ’ 2) โˆ’ 4 (2๐‘ก + 3))/12=2/3โˆ’๐‘ก (9๐‘ก โˆ’ 6 โˆ’ 8๐‘ก โˆ’ 12)/12=2/3โˆ’๐‘ก (9๐‘ก โˆ’ 8๐‘ก โˆ’ 6 โˆ’ 12)/12=2/3โˆ’๐‘ก (๐‘ก โˆ’ 18)/12=2/3โˆ’๐‘ก (๐‘ก โˆ’ 18)/12=(2 โˆ’ 3๐‘ก)/3 3 (t โˆ’ 18) = 12 (2 โˆ’ 3t) 3t โˆ’ 54 = 24 โˆ’ 36t 3t + 36t โˆ’ 54 = 24 39t โˆ’ 54 = 24 39t = 24 + 54 39t = 78 t = 78/39 t = 2 Check:- L.H.S (3๐‘ก โˆ’ 2)/4โˆ’(2๐‘ก + 3)/3=(3(2) โˆ’ 2)/4 โˆ’(2(2) + 3 )/3 = (6 โˆ’ 2)/4โˆ’(4 + 3)/3=4/4โˆ’ 7/3=1โˆ’7/3 = (3 โˆ’ 7)/3=(โˆ’4)/3 R.H.S 2/3โˆ’๐‘ก = 2/3โˆ’2=(2 โˆ’ 6)/3=(โˆ’4)/3

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.