# Example 7 - Chapter 2 Class 8 Linear Equations in One Variable

Last updated at June 21, 2018 by Teachoo

Last updated at June 21, 2018 by Teachoo

Transcript

Example 7The present age of Sahil’s mother is three times the present age of Sahil. After 5 years their ages will add to 66 years. Find their present ages.Let Sahil’s age = x years His Mother’s age = 3x years After 5 years Sahil’s age = (x + 5) years Mother’s age = (3x + 5) years Given, Sum of their ages after 5 years = 66 (x + 5) + (3x + 5) = 66 (x + 3x) + (5 + 5) = 66 4x + 10 = 66 4x = 66 − 10 4x = 56 x = 56/4 x = 14 ∴ Sahil’s present age = x = 14 years Sahil’s Mother present age is = 3x = 3 × 14 = 42 years

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.