# Example 7 - Chapter 2 Class 8 Linear Equations in One Variable

Last updated at June 21, 2018 by Teachoo

Examples

Example 1

Example 2

Example 3 Important

Example 4

Example 5

Example 6 Important

Example 7 Important You are here

Example 8

Example 9

Example 10 Important

Example 11 Important

Example 12

Example 13

Example 14 Important

Example 15

Example 16 Important

Example 17

Example 18 Important

Example 19 Important

Last updated at June 21, 2018 by Teachoo

Example 7 The present age of Sahil’s mother is three times the present age of Sahil. After 5 years their ages will add to 66 years. Find their present ages.Let Sahil’s age = x years His Mother’s age = 3x years After 5 years Sahil’s age = (x + 5) years Mother’s age = (3x + 5) years Given, Sum of their ages after 5 years = 66 (x + 5) + (3x + 5) = 66 (x + 3x) + (5 + 5) = 66 4x + 10 = 66 4x = 66 − 10 4x = 56 x = 56/4 x = 14 ∴ Sahil’s present age = x = 14 years Sahil’s Mother present age is = 3x = 3 × 14 = 42 years