Example 9 - The sum of three consecutive multiples of 11 is 363

Example 9 - Chapter 2 Class 8 Linear Equations in One Variable - Part 2

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Transcript

Question 9 The sum of three consecutive multiples of 11 is 363. Find these multiples.Let first multiple = x Second multiple = x + 11 Third multiple = (x + 11) + 11 = x + 22 Given Sum of multiples is 363 x + (x + 11) + (x + 22) = 363 (x + x + x) + (11 + 22) = 363 3x + 33 = 363 3x = 363 – 33 Rough Multiples of 11 are 11, 22, 33,.. Consecutive multiples are 11, 22, 33 Difference between two Consecutive multiples = 11 If 1st multiple is 11, then 2nd multiple = 11 + 11 = 22 3rd multiple = 22 + 11 = 33 3x = 330 x = 330/3 x = 110 Therefore, ∴ First multiple = x = 110 Second multiple = x + 11 = 110 + 11 = 121 Third multiple = x + 22 = 110 + 22 = 132

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.