Example 4 - Chapter 2 Class 8 Linear Equations in One Variable

Last updated at April 16, 2024 by

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Example 4 Solve 5x – 2 (2x – 7) = 2 (3x – 1) + 7/( 2)5x − 2 (2x − 7) = 2 (3x − 1) + 7/2 5x − 4x + 14 = 2 (3x − 1) + 7/2 5x − 4x + 14 = 6x − 2 + 7/2 x + 14 = 6x − 2 + 𝟕/𝟐 x + 14 = (12𝑥 − 4 + 7)/2 x + 14 = (𝟏𝟐𝒙 + 𝟑)/𝟐 2 (x + 14) = 12x + 3 2x + 28 = 12x + 3 12x + 3 = 2x + 28 12x − 2x + 3 = 28 10x + 3 = 28 10x = 28 − 3 10x = 25 x = 25/10 x = 𝟓/𝟐 L.H.S 5𝑥−2(2𝑥−7) = 5× 5/2−2(2×5/2−7) = 25/2−2(5−7) = 25/2−2 (−2) =25/2 + 4 =(25 + 8)/2 =𝟑𝟑/𝟐 R.H.S 2(3𝑥−1)+7/2 = 2(3× 5/2−1)+7/2 = 2(15/2−1)+7/2 =2((15 − 2)/2)+7/2 =2(13/2)+7/2 = 26/2+7/2 =𝟑𝟑/𝟐 ∴ LHS = RHS Hence Verified.

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.