Example 4 - Chapter 2 Class 8 Linear Equations in One Variable

Last updated at August 8, 2026 by

Example 4 - Solve 5x - 2 (2x - 7) = 2 (3x - 1) + 7/2 - Chapter 2 - Examples

part 2 - Example 4 - Examples - Serial order wise - Chapter 2 Class 8 Linear Equations in One Variable
part 3 - Example 4 - Examples - Serial order wise - Chapter 2 Class 8 Linear Equations in One Variable

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Example 4 Solve 5x – 2 (2x – 7) = 2 (3x – 1) + 7/( 2)5x − 2 (2x − 7) = 2 (3x − 1) + 7/2 5x − 4x + 14 = 2 (3x − 1) + 7/2 5x − 4x + 14 = 6x − 2 + 7/2 x + 14 = 6x − 2 + 𝟕/𝟐 x + 14 = (12𝑥 − 4 + 7)/2 x + 14 = (𝟏𝟐𝒙 + 𝟑)/𝟐 2 (x + 14) = 12x + 3 2x + 28 = 12x + 3 12x + 3 = 2x + 28 12x − 2x + 3 = 28 10x + 3 = 28 10x = 28 − 3 10x = 25 x = 25/10 x = 𝟓/𝟐 L.H.S 5𝑥−2(2𝑥−7) = 5× 5/2−2(2×5/2−7) = 25/2−2(5−7) = 25/2−2 (−2) =25/2 + 4 =(25 + 8)/2 =𝟑𝟑/𝟐 R.H.S 2(3𝑥−1)+7/2 = 2(3× 5/2−1)+7/2 = 2(15/2−1)+7/2 =2((15 − 2)/2)+7/2 =2(13/2)+7/2 = 26/2+7/2 =𝟑𝟑/𝟐 ∴ LHS = RHS Hence Verified.

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