Question 4 - Solving Linear Equations - Making equation simpler and then solving - Chapter 2 Class 8 Linear Equations in One Variable

Last updated at April 16, 2024 by

Ex 2.6, 4 - Solve 3y + 4/ 2 - 6y = -2/5 - Chapter 2 Class 8 NCERT

Ex 2.6, 4 - Chapter 2 Class 8 Linear Equations in One Variable - Part 2

Transcript

Question 4 Solve the following equations. (3 + 4)/(2 6 )= ( 2)/5 (3 + 4)/(2 6 )= ( 2)/5 5 (3y + 4) = 2 (2 6y) 15y + 20 = 2(2 6y) 15y + 20 = 4 + 12y 15y 12y + 20 = 4 3y + 20 = 4 3y = 4 20 3y = 24 y = ( 24)/3 y = 8 Check:- L.H.S = (3 + 4)/(2 6 ) =(3( 8) + 4)/(2 6( 8))=( 24 + 4)/(2 + 48)=( 20)/50 =( 2)/5 = R.H.S LHS = RHS Hence Verified.

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.