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Forming Linear Equations - Cost, Sale, Profit
Forming Linear Equations - Cost, Sale, Profit
Last updated at May 29, 2023 by Teachoo
Question 7 Hasan buys two kinds of cloth materials for school uniforms, shirt material that costs him Rs 50 per metre and trouser material that costs him Rs 90 per metre. For every 2 meters of the trouser material he buys 3 metres of the shirt material. He sells the materials at 12% and 10% profit respectively. His total sale is Rs 36,660. How much trouser material did he buy?Given, Cost of shirt material = Rs 50 per meter & Cost of trouser material = Rs 90 per meter For every 3 meters of the shirt material, he buys 2 meter of the trouser material. (πβπππ‘ πππ‘πππππ ππ’ππβππ ππ)/(ππππ’π ππ πππ‘πππππ ππ’ππβππ ππ)=3/2 Let shirt material purchased = 3π₯ meters & trouser material purchased = 2π₯ meters Shirt material Cost price = Cost of 1 meter Γ Quantity = 50 Γ 3π₯ = (50 Γ 3) π₯ = 150π₯ Hasan sells the shirt material at 12% profit Profit = 12% Γ Cost price = 12/100Γ150π₯ = 18π₯ Sell Price = Cost price + Profit = 150π₯ + 18π₯ = 168π₯ Let shirt material purchased = 3π₯ meters & trouser material purchased = 2π₯ meters Shirt material Cost price = Cost of 1 meter Γ Quantity = 50 Γ 3π₯ = (50 Γ 3) π₯ = 150π₯ Hasan sells the shirt material at 12% profit Profit = 12% Γ Cost price = 12/100Γ150π₯ = 18π₯ Trouser material Cost price = Cost of 1 meter Γ Quantity = 90 Γ 2π₯ = (90 Γ 2) π₯ = 180π₯ Hasan sells the trouser material at 10% profit Profit = 10% Γ Cost price = 10/100Γ180π₯ = 18π₯ Trouser material Cost price = Cost of 1 meter Γ Quantity = 90 Γ 2π₯ = (90 Γ 2) π₯ = 180π₯ Hasan sells the trouser material at 10% profit Profit = 10% Γ Cost price = 10/100Γ180π₯ = 18π₯ Therefore, Sell price of shirt material = 168π₯ and Sell price of trouser material = 198π₯ Given that Hasan's total sale amount = Rs 36,600 Sell price of shirt material + Sell price of trouser material = Rs 36,600 168π₯ + 198π₯ = 36,600 366π₯ = 36,600 π₯ = 36600/366 π₯ = 100 β΄ Quantity of the trouser material Hasan buys = 2π₯ = (2 Γ 100) = 200 meters