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Last updated at June 21, 2018 by Teachoo

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Example 9 The sum of three consecutive multiples of 11 is 363. Find these multiples.Let first multiple = x Second multiple = x + 11 Third multiple = (x + 11) + 11 = x + 22 Given Sum of multiples is 363 x + (x + 11) + (x + 22) = 363 (x + x + x) + (11 + 22) = 363 3x + 33 = 363 3x = 363 – 33 Rough Multiples of 11 are 11, 22, 33,.. Consecutive multiples are 11, 22, 33 Difference between two Consecutive multiples = 11 If 1st multiple is 11, then 2nd multiple = 11 + 11 = 22 3rd multiple = 22 + 11 = 33 3x = 330 x = 330/3 x = 110 Therefore, ∴ First multiple = x = 110 Second multiple = x + 11 = 110 + 11 = 121 Third multiple = x + 22 = 110 + 22 = 132

Forming Linear Equations - Consecutive Multiples

Chapter 2 Class 8 Linear Equations in One Variable

Concept wise

- Definitions
- Solving Linear Equations - Variables on 1 side
- Solving Linear Equations - Variables on both sides
- Solving Linear Equations - Making equation simpler and then solving
- Forming Linear Equations - Perimeter and Area
- Forming Linear Equations - Fraction - Denominator & Numerator
- Forming Linear Equations - Cost, Sale, Profit
- Forming Linear Equations - Consecutive Numbers
- Forming Linear Equations - Consecutive Multiples
- Forming Linear Equations - Coins and Currency Notes
- Forming Linear Equations - Adding subtracting numbers
- Forming Linear Equations - Two digit number
- Forming Linear Equations - Age

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.