Ex 2.2, 7 - Simplify and solve 3(t - 3) = 5(2t + 1) - Class 8 - Ex 2.2

part 2 - Ex 2.2, 7 - Ex 2.2 - Serial order wise - Chapter 2 Class 8 Linear Equations in One Variable

Remove Ads

Transcript

Ex 2.2, 7 Simplify and solve the following linear equations. 3 (t – 3) = 5 (2t + 1) 3 (t – 3) = 5 (2t + 1) 3t − 9 = 5 (2t + 1) 3t − 9 = 10t + 5 3t − 10t − 9 = 5 −7t − 9 = 5 −7t = 5 + 9 −7t = 14 t = 14/(−7) t = −2 Check:- ∴ LHS = RHS Hence Verified. R.H.S 5(2t + 1) = 5 (2(−2) + 1) = 5 (−4 + 1) = 5 (−3) = −15

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.