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Ex 2.2, 10 - Chapter 2 Class 8 Linear Equations in One Variable
Last updated at August 14, 2026 by Teachoo
Solving Linear Equations - Making equation simpler and then solving
Chapter 2 Class 8 Linear Equations in One Variable
Concept wise
- Definitions
- Solving Linear Equations - Variables on 1 side
- Solving Linear Equations - Variables on both sides
-
Solving Linear Equations - Making equation simpler and then solving
- Forming Linear Equations - Perimeter and Area
- Forming Linear Equations - Fraction - Denominator & Numerator
- Forming Linear Equations - Cost, Sale, Profit
- Forming Linear Equations - Consecutive Numbers
- Forming Linear Equations - Consecutive Multiples
- Forming Linear Equations - Coins and Currency Notes
- Forming Linear Equations - Adding subtracting numbers
- Forming Linear Equations - Two digit number
- Forming Linear Equations - Age
Transcript
Ex 2.2, 10 Simplify and solve the following linear equations. 0.25 (4f โ 3) = 0.05 (10f โ 9)0.25 (4f โ 3) = 0.05 (10f โ 9) 25/100 (4๐ โ3)=5/100(10๐ โ 9) 1/4 (4๐ โ3)=1/20 (10๐ โ9) (๐๐ โ ๐)/๐=(๐๐๐ โ ๐)/๐๐ 20 (4f โ 3) = 4(10f โ 9) 80f โ 60 = 4(10f โ 9) 80f โ 60 = 40f โ 36 80f โ 40f โ 60 = โ36 40f โ 60 = โ 36 40f = โ36 + 60 40f = 24 f = 24/40 f = ๐/๐๐ = 0.6 Check:- L.H.S 0.25 (4f โ 3) = 0.25 (4 ร 0.6 โ 3) = 0.25 (4 ร 6/10 โ 3) = 0.25 (24/10 โ 3) = 0.25 ((24 โ 30)/10) = 0.25 ((โ6)/10) = 25/100 ร ((โ6)/10) = (โ150)/1000 = (โ15)/100 = โ 0.15 R.H.S 0.05 (10f โ 9) = 0.05 (10 ร 0.6 โ 9) = 0.05 (10 ร 6/10 โ 9) = 0.05 (6 โ 9) = 0.05 ร (โ3) = 5/100 ร (โ3) = (โ15)/100 = โ 0.15 โด LHS = RHS , Hence Verified
