Ex 2.2, 6 - Solve m-m/1 = 1- m-2/3 - Chapter 2 Class 8 - NCERT Maths - Ex 2.2

part 2 - Ex 2.2, 6 - Ex 2.2 - Serial order wise - Chapter 2 Class 8 Linear Equations in One Variable
part 3 - Ex 2.2, 6 - Ex 2.2 - Serial order wise - Chapter 2 Class 8 Linear Equations in One Variable

Remove Ads

Transcript

Ex 2.2, 6 Solve the following linear equations. š‘šāˆ’(š‘š āˆ’ 1)/2=1āˆ’(š‘š āˆ’ 2)/3š‘šāˆ’(š‘š āˆ’ 1)/2=1āˆ’(š‘š āˆ’ 2)/3 (2š‘š āˆ’ (š‘š āˆ’ 1))/2=1āˆ’ (š‘š āˆ’ 2)/3 (šŸš’Ž āˆ’ š’Ž + šŸ)/šŸ=šŸāˆ’ (š’Ž āˆ’ šŸ)/šŸ‘ ( š‘š + 1)/2=1āˆ’(š‘š āˆ’ 2)/3 ( š‘š + 1)/2=(3 āˆ’ (š‘š āˆ’ 2))/3 ( š‘š + 1)/2=(3 āˆ’ š‘š + 2)/3 ( š‘š + 1)/2=(5 āˆ’ š‘š)/3 3 (m + 1) = 2 (5 āˆ’ m) 3m + 3 = 2 (5 āˆ’ m) 3m + 3 = 10 āˆ’ 2m 3m + 2m + 3 = 10 5m + 3 = 10 5m + 3 = 10 5m = 10 āˆ’ 3 5m = 7 m = šŸ•/šŸ“ Check:- L.H.S š‘šāˆ’(š‘š āˆ’ 1)/2 =7/5āˆ’(7/5 āˆ’ 1)/2 = 7/5āˆ’ ( (7 āˆ’ 5)/5 )/2=7/5āˆ’2/10 =7/5āˆ’1/5=6/5 R.H.S 1āˆ’(š‘š āˆ’ 2)/3 =1āˆ’(7/5 āˆ’ 2)/3 = 1āˆ’ ( (7 āˆ’ 2(5))/5 )/3= 1 – ((7 āˆ’ 10)/5)/3 = 1 – (āˆ’3/5)/3 = 1 + 3/15 =1+1/5=šŸ”/šŸ“ ∓ LHS = RHS Hence Verified.

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.