Ex 2.2, 7 - The sum of three consecutive multiples of 8 is 888. Find

Ex 2.2, 7 - Chapter 2 Class 8 Linear Equations in One Variable - Part 2

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Question 7 The sum of three consecutive multiples of 8 is 888. Find the multiples.Let first multiple = x Second multiple = x + 8 Third multiple = (x + 8) + 8 = x + 16 Given, Sum of multiples = 888 x + (x + 8) + (x + 16) = 888 x + x + x + 8 + 16 = 888 3x + 24 = 888 3x = 888 − 24 Rough Multiple of 8 are 8, 16, 24, 32,.. Consecutive Multiple are 8, 16, 24 Difference Between two Multiples = 8 If 1st multiple is 8 then 2nd multiple = 8 + 8 = 16 3rd multiple = 16 + 8 = 24 3x = 864 x = (864 )/3 x = 288 Thus, ∴ First multiple = x = 288 Second multiple = x + 8 = 288 + 8 = 296 Third multiple = x + 16 = 288 + 16 = 304

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.