Ex 2.2, 3 - Solve x + 7 - 8x/3 = 17/6 - 5x/2 - Chapter 2 Class 8 - Ex 2.2

part 2 - Ex 2.2, 3 - Ex 2.2 - Serial order wise - Chapter 2 Class 8 Linear Equations in One Variable

Remove Ads

Transcript

Ex 2.2, 3 Solve the following linear equations. x + 7 − 8𝑥/3=17/6−5𝑥/2x + 7 − 8𝑥/3=17/6−5𝑥/2 (𝟑(𝒙 + 𝟕) − 𝟖𝒙)/𝟑=(𝟏𝟕 − 𝟓𝒙 × 𝟑)/𝟔 (3𝑥 + 21 − 8𝑥)/3=(17 − 15𝑥)/6 (3𝑥 − 8𝑥 + 21)/3=(17 − 15𝑥)/6 (−5𝑥 + 21)/3=(17 − 15𝑥)/6 6 (−5x + 21) = 3 (17 − 15x) −30x + 126 = 51 − 45x −30x = −45x + 51 − 126 −30x = −45x − 75 −30x + 45x = −75 15x = − 75 x = (−75)/15 x = −5 Check:- ∴ LHS = RHS Hence Verified. L.H.S 𝑥+7−8𝑥/3 =−5+7−(8 (−5))/3 =2+40/3 =(6 + 40)/3=46/3 R.H.S 17/6−5𝑥/2 =17/6−5(−5)/2=17/6+25/2 =(17 +3(25))/6 =(17 + 75)/6=92/6=46/3

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.