Theorem 10.4 - Class 9 - Line drawn from centre to bisect chord.jpg

2 Theorem 10.4 - Class 9 - AXO = BXO = 90 OX AB Hence Proved.jpg

  1. Chapter 10 Class 9 Circles
  2. Serial order wise
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Transcript

Theorem 10.4 The line drawn through the centre of a circle to bisect a chord is perpendicular to the chord. Given : A circle with center at O. AB is chord of circle & OX bisects AB i.e. AX = BX To Prove : OX AB Proof : In AOX = BOX OA = OB OX = OX AX = BX AOX BOX AXO = BXO In line AB, Hence, AXO and BXO form linear Pair AXO + BXO = 180 AXO + AXO = 180 2 AXO = 180 AXO = 180 2 AXO = 90 AXO = BXO = 90 OX AB Hence, Proved.

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.