

Subscribe to our Youtube Channel - https://you.tube/teachoo
Last updated at Dec. 10, 2019 by Teachoo
Transcript
Ex 9.3, 10 Form the differential equation of the family of circle having a center on y-axis and radius 3 units. General equation of circle is :- (๐ฅโ๐)^2+(๐ฆโ๐)^2=๐^2 Given center is on y-axis โด Center = (0, b) And, Radius = 3 Hence, our equation becomes (๐ฅโ0)^2+(๐ฆโ๐)^2=(3)^2 ๐ฅ^2+(๐ฆโ๐)^2=9 Differentiating Both Sides w.r.t. ๐ฅ 2๐ฅ+2(๐ฆโ๐)[๐๐ฆ/๐๐ฅโ0]=0 2๐ฅ+2(๐ฆโ๐)๐ฆโฒ=0 2[๐ฅ+(๐ฆโ๐)๐ฆโฒ]=0 ๐ฅ+(๐ฆโ๐) ๐ฆ^โฒ=0 (๐ฆโ๐)๐ฆโฒ=โ๐ฅ (๐ฆโ๐)= (โ๐ฅ)/๐ฆ^โฒ Putting the value of (๐ฆโ๐) in equation (1) x2 + (y โ b)2 = 9 ๐ฅ^2+[(โ๐ฅ)/๐ฆ^โฒ ]^2=9 ๐ฅ^2+๐ฅ^2/ใ๐ฆ^โฒใ^2 =9 (๐ฅ^2 ใ๐ฆ^โฒใ^2+ ๐ฅ^2)/ใ๐ฆ^โฒใ^2 =9 ๐ฅ^2 ใ๐ฆ^โฒใ^2+๐ฅ^2=9ใ๐ฆ^โฒใ^2 ๐ฅ^2 ใ๐ฆ^โฒใ^2โ9ใ๐ฆ^โฒใ^2+๐ฅ^2=0 ใ๐ฆ^โฒใ^2 (๐ฅ^2โ9)+๐ฅ^2=0 โด (๐^๐โ๐) ใ๐^โฒใ^๐+๐^๐=๐
Ex 9.3
Ex 9.3, 2 Not in Syllabus - CBSE Exams 2021
Ex 9.3, 3 Important Not in Syllabus - CBSE Exams 2021
Ex 9.3, 4 Not in Syllabus - CBSE Exams 2021
Ex 9.3, 5 Important Not in Syllabus - CBSE Exams 2021
Ex 9.3, 6 Not in Syllabus - CBSE Exams 2021
Ex 9.3, 7 Important Not in Syllabus - CBSE Exams 2021
Ex 9.3, 8 Not in Syllabus - CBSE Exams 2021
Ex 9.3, 9 Not in Syllabus - CBSE Exams 2021
Ex 9.3, 10 Important Not in Syllabus - CBSE Exams 2021 You are here
Ex 9.3, 11 Not in Syllabus - CBSE Exams 2021
Ex 9.3, 12 Not in Syllabus - CBSE Exams 2021
About the Author