# Misc 13

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Misc 13 Find the points at which the function f given by f (𝑥) = 𝑥−24 𝑥+13 has (i) local maxima (ii) local minima (iii) point of inflexion f𝑥= 𝑥−24𝑥+13 Step 1: Finding f’𝑥 f’𝑥 = 𝑑 𝑥−24𝑥+13𝑑𝑥 = 𝑥−24′𝑥+13+𝑥+13′𝑥−24 = 4𝑥−23𝑥+13+3𝑥+12𝑥−24 = 𝑥−23𝑥+124𝑥+1+3𝑥−2 = 𝑥−23𝑥+124𝑥+4𝑥+3𝑥−6 = 𝑥−23𝑥+127𝑥−2 Step 2: Putting f’𝑥=0 𝑥−23𝑥+127𝑥−2=0 Hence, 𝑥=2 & 𝑥=−1 & 𝑥=27 = 0.28 Step 3: Thus 𝑥=−1 is a point of inflexion 𝑥=27 is point of minima & 𝑥=2 is point of maxima

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Class 12

Important Question for exams Class 12

- Chapter 1 Class 12 Relation and Functions
- Chapter 2 Class 12 Inverse Trigonometric Functions
- Chapter 3 Class 12 Matrices
- Chapter 4 Class 12 Determinants
- Chapter 5 Class 12 Continuity and Differentiability
- Chapter 6 Class 12 Application of Derivatives
- Chapter 7 Class 12 Integrals
- Chapter 8 Class 12 Application of Integrals
- Chapter 9 Class 12 Differential Equations
- Chapter 10 Class 12 Vector Algebra
- Chapter 11 Class 12 Three Dimensional Geometry
- Chapter 12 Class 12 Linear Programming
- Chapter 13 Class 12 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.