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Last updated at Aug. 13, 2018 by Teachoo
Transcript
AA Criteria If two angles of one triangle are respectively equal to two angles of another triangle, then the two triangles are similar.Given: Two triangles ∆ABC and ∆DEF such that ∠B = ∠E & ∠C = ∠F To Prove: ∆ABC ~ ∆DEF Proof: In ∆ ABC, By angle sum property ∠A + ∠B + ∠C = 180° In ∆ DEF, By angle sum property ∠D + ∠E + ∠F = 180° In ∆ DEF, By angle sum property ∠D + ∠E + ∠F = 180° From (1) and (2) ∠A + ∠B + ∠C = ∠D + ∠E + ∠F ∠A + ∠E + ∠F = ∠D + ∠E + ∠F ∠ A = ∠ D Thus, In Δ ABC & Δ DEF ∠ A = ∠ D ∠ B = ∠ E ∠ C = ∠ F ∴ Δ ABC ~ Δ DEF Hence, proved
Theorems
Theorem 6.2 - Converse of Basic Proportionality Theorem
Theorem 6.3
AA Similarity Criteria You are here
Theorem 6.4
Theorem 6.5
Theorem 6.6 Not in Syllabus - CBSE Exams 2021
Theorem 6.7 Important Not in Syllabus - CBSE Exams 2021
Theorem 6.8
Theorem 6.9
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