Misc 13 (MCQ) - Chapter 13 Class 12 Probability

Last updated at April 16, 2024 by

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Misc 13 If A and B are any two events such that P(A) + P(B) – P(A and B) = P(A), then (A) P(B|A) = 1 (B) P(A|B) = 1 (C) P(B|A) = 0 (D) P(A|B) = 0 Here P(A and B) = P(A ∩ B) Now, P(A) + P(B) – P(A and B) = P(A) P(A) + P(B) – P(A ∩ B) = P(A) P(B) – P(A ∩ B) = P(A) – P(A) P(B) – P(A ∩ B) = 0 P(B) = P(A ∩ B) P(B) = P(A ∩ B) Dividing By P(B) 1 = (𝑃(𝐴 ∩ 𝐵))/(𝑃(𝐵)) (𝑷(𝑨 ∩ 𝑩))/(𝑷(𝑩)) = 1 Also, P(A|B) = (𝑃(𝐴 ∩ 𝐵))/(𝑃(𝐵)) So, P(A|B) = 1 Hence, Option (B) is Correct.

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.