Misc 13 (MCQ) - Chapter 13 Class 12 Probability

Last updated at Dec. 16, 2024 by

Misc 13 (MCQ) - If P(A) + P(B) - P(A and B) = P(A), then P(B|A) - Miscellaneous

part 2 - Misc 13 (MCQ) - Miscellaneous - Serial order wise - Chapter 13 Class 12 Probability

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Misc 13 If A and B are any two events such that P(A) + P(B) – P(A and B) = P(A), then (A) P(B|A) = 1 (B) P(A|B) = 1 (C) P(B|A) = 0 (D) P(A|B) = 0 Here P(A and B) = P(A ∩ B) Now, P(A) + P(B) – P(A and B) = P(A) P(A) + P(B) – P(A ∩ B) = P(A) P(B) – P(A ∩ B) = P(A) – P(A) P(B) – P(A ∩ B) = 0 P(B) = P(A ∩ B) P(B) = P(A ∩ B) Dividing By P(B) 1 = (𝑃(𝐴 ∩ 𝐵))/(𝑃(𝐵)) (𝑷(𝑨 ∩ 𝑩))/(𝑷(𝑩)) = 1 Also, P(A|B) = (𝑃(𝐴 ∩ 𝐵))/(𝑃(𝐵)) So, P(A|B) = 1 Hence, Option (B) is Correct.

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo